A bullet of mass 3 kg is fired at a speed of 108 km/hr towards a block of mass 12 kg placed on the ground. It was observed that the bullet penetrates into the block & comes out at a speed of 15 m/s. Find the speed acquired by the block.
A
3.75 m/s
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B
5.25 m/s
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C
4.25 m/s
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D
2.25 m/s
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Solution
The correct option is A 3.75 m/s Applying conservation of momentum pi=pf 3×(108×518)=3×15+12×v 3 × 30 = 45 + 12v 12v= 45 ⇒v= 3.75 m/s