A bullet of mass 5 gram is fired from a gun with a speed of 250 metre per second in 10 seconds what force Does It Act on the gun

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Solution

Let's take the direction of bullet traveling as positive and direction of gun traveling as negative.

In both cases according to Newton's third law,
Force on bullet= - Force on gun
We know that f=ma=mv/t

m=5g=0.005kg
v=250m/s
t=10sec

F=0.005×250/10
=0.125N

Therefore force on gun = -0.125N

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A bullet of mass 5 gram is fired from a gun with a speed of 250 metre per second in 10 seconds what force Does It Act on the gun

Let's take the direction of bullet traveling as positive and direction of gun traveling as negative. In both cases according to Newton's third law, Force on bullet= - Force on gun We know that f=ma=mv/t m=5g=0.005kg v=250m/s t=10sec F=0.005×250/10 =0.125N Therefore force on gun = -0.125N

Let's take the direction of bullet traveling as positive and direction of gun traveling as negative.

In both cases according to Newton's third law,
Force on bullet= - Force on gun
We know that f=ma=mv/t

m=5g=0.005kg
v=250m/s
t=10sec

F=0.005×250/10
=0.125N

Therefore force on gun = -0.125N