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Question

# A bullet of mass 5 g, travelling with a speed of 210 m/s, strikes a fixed wooden target. One half of its kinetic energy is converted into heat in the bullet while the other half is converted into heat in the wood. The rise of temperature of the bullet, if the specific heat of its material is 0.030 cal/(g°C) (1 cal=4.2×107 ergs) close to

A
87.5° C
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B
83.3° C
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C
119.2° C
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D
38.4° C
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Solution

## The correct option is A 87.5° CAccording to question, one half of its kinetic energy is converted into heat in the wood. 12mv2×12=msΔT ⇒ΔT=v24×s=210×2104×4.2×0.03×1000=87.5° C

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