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Question

A bullet of mass 50g is moving with a velocity of 500m/s. It penetrates 10cm into a still target and comes to rest. Calculate:

  1. the kinetic energy possessed by the bullet, and
  2. the average retarding force offered by the target

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Solution

Step 1: Given

Mass of the bullet, m=50g=0.05kg

Velocity of the bullet, v=500m/s

Distance penetrated by the bullet, s=10cm=0.1m

Step 2: Calculate the kinetic energy

KE=12mv2=12×0.05×(500)2=6250kg-m2/s2=6250J

Step 3: Determine the average retarding force

Work done is given by, W=Force×Distance

In this situation, Work done = Resistance force x distance

W=KE=6250=F×0.1F=62500N

Therefore,

  1. the kinetic energy possessed by the bullet is 6250N
  2. the average retarding force offered by the target is 62500N

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