1
You visited us
1
times! Enjoying our articles?
Unlock Full Access!
Byju's Answer
Standard XII
Physics
Instantaneous Force and Impulse
A bullet of m...
Question
A bullet of mass
60
g moving with the velocity of
500
m/s is brought to rest in
0.01
s. Its impulse will be?
Open in App
Solution
v = u + at
0 = 500 + a(0.01)
a = -50000
F = ma
F
=
0.06
×
(
−
50000
)
F
=
−
3000
N
impulse,J = Ft
J =
3000
×
0.01
J
=
30
N
s
Suggest Corrections
0
Similar questions
Q.
A bullet of mass 60 g moving with a velocity of
500
m
s
−
1
is brought to rest in 0.01 s. Find the impulse and the average force of the blow.
Q.
A bullet of mass
25
g
moving with a velocity of
150
m
/
s
a strikes a target and is brought to rest in
1
100
of second. What is the impulse?
Q.
A bullet of mass 0.1 kg moving horizontally with a velocity of 20 m/s strikes a target and brought to rest in 0.1 s. Find the impulse and average force of impact.
Q.
A cricket ball of mass 100g moving with a velocity of 20m/s is brought to rest by a player in 0.05s the impulse of the ball is
Q.
A bullet of mass
0.1
k
g
moving horizontally with a velocity of
20
m
/
s
strikes a stationary target & is brought to rest in
0.1
s
. find the impulse & average force of impact
View More
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
Related Videos
Summary and Misconceptions
PHYSICS
Watch in App
Explore more
Instantaneous Force and Impulse
Standard XII Physics
Join BYJU'S Learning Program
Grade/Exam
1st Grade
2nd Grade
3rd Grade
4th Grade
5th Grade
6th grade
7th grade
8th Grade
9th Grade
10th Grade
11th Grade
12th Grade
Submit
AI Tutor
Textbooks
Question Papers
Install app