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Newton's Second Law

A bullet of m...

Question

A bullet of mass 7g is fired into a block of metal weighing 7kg. The block is free to move. After the impact the velocity of the bullet and block is 70m/s.what is the initial velocity of the bUllet?

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Solution

Dear student,

Since no external force hence net momentum will be conserve.
$m_{1}$ $u_{1}$ + $m_{2} u_{2} = m_{1} v_{1 +} m_{2} v_{2}$ ( since final velocity of both particals are same hence $v_{1} = v_{2} = v (l e t)$ = 70m/s
$m_{1}$ $u_{1}$ + $m_{2} u_{2} = (m_{1} + m_{2}) v$
.007 $u_{1}$ + 0 = (7 + .007)*70
$u_{1}$ = 70070 m/s

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