wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A bullet of mass m = 50 gm strikes a bag of mass M = 5 kg hanging from a fixed point, with a horizontal velocity ¯Vp. If bullet sticks to the sand bag then just after collision the ratio of final & initial kinetic energy of the bullet is approximately :

A
102
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
103
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
106
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
104
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 104
By momentum conservation we have
mVp=(m+M)V ,m=0.05 kg
0.05×Vp=(5+0.05)VVp=101V
initial KE of bullet=mV2p2
Final KE=mV22
So ratio =mV2mV2p=104

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Conservation of Momentum
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon