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Question

A bullet of mass m=50 gm strikes (Δt0) a sand bag of mass M=5 kg hanging from a fixed point, with a horizontal velocity vp. If bullet sticks to the sand bag then just after collision the ratio of final and initial kinetic energy of the bullet is?

A
102
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B
103
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C
106
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D
104
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Solution

The correct option is D 104
According to Conservation of Momentum,
mvp = (m+M)V where
m is the mass of the bullet, 
vp is the velocity of the bullet before collision, 
M is the mass of the sandbag and V is the velocity after the collision
0.05* vp  = (0.050+5)V
vp = [5.050/0.05] V = 101 V 
Ratio of final KE to initial KE = [0.5mV2] / [0.5mvp2] = 
10‑4  (approx.)


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