Question

A bullet of mass $m$ is fired upward in a direction of angle of projection ${60}^o$ with an initial velocity $u$. The angular momentum of this bullet when it is crossing highest point with respect to point of projection is:

• A. $\frac{2m{u}^3}{5g}$
• B. $\frac{3m{u}^3}{8g}$
• C. $\frac{2m{u}^3}{9g}$
• D. $\frac{3m{u}^3}{16g}$

Answer 1

The correct option is D $\frac{3m{u}^3}{16g}$

At highest point Velocity $V=ucos{60}^o=u/2$

Maximum height $h=\frac{(usin60{)}^2}{2g}=\frac{3u^2}{8g}$

So angular momentum $=mVh=\frac{3m{u}^3}{16g}$