A bullet of mass X, moving with a velocity V, strikes a wooden block of mass Z and gets embedded. If the block is free to move, its velocity after impact will be.
A
XX+ZV
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B
X+ZZV
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C
XX−ZV
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D
X+ZXV
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Solution
The correct option is AXX+ZV
REF.Image.
Initial momentum =XV+0=Pi
Final momentum =Vf+(Z+X)=Pf
Applying linear momentum conservation on (bullet f block)