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Question

A bullet with muzzle velocity 1002 m/s is to be fired at an angle of 45 with the horizontal. Find the coordinates of bullet after t=4 s, assuming bullet was initially at origin. Take g=10 m/s2.

A
400 m,320 m
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B
400 m,240 m
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C
140 m,290 m
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D
40 m,165 m
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Solution

The correct option is A 400 m,320 m
Given;
u=1002 m/s
θ=45 from horizontal
t=4 s
Reference : Upward vertical direction is taken +ve
ay=g
For horizontal direction:
X=ux×t=ucosθ×t
X=1002×cos45×4
X=400 m

For vertical direction:
Y=uy×t12ayt2
Y=usin45×412×10×42
=1002×12×480
=40080
Y=320 m
Coordinates of bullet at t=4 s
(X,Y)=(400 m,320 m)

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