A bullets leaves a rifle with a velocity of 200m/s and strikes a wooden target up to 4cm.What velocity should it have to pierce the same block of wood up to16cm?

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Solution

$v = 200 m / s e c, d = 4 c m t i m e, t = \frac{4}{200 \times 10^{2}} = . 002 s e c v = \frac{16 \times 10^{- 2}}{. 002} = 80 m / s e c$

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A bullets leaves a rifle with a velocity of 200m/s and strikes a wooden target up to 4cm.What velocity should it have to pierce the same block of wood up to16cm?

v=200m/sec,d=4cmtime,t=4200×102=.002secv=16×10-2.002=80m/sec

$v = 200 m / s e c, d = 4 c m t i m e, t = \frac{4}{200 \times 10^{2}} = . 002 s e c v = \frac{16 \times 10^{- 2}}{. 002} = 80 m / s e c$