A burner is supplying heat at a rate of 50 Js^-1. A solid of specific heat capacity 0.72 Jg^-1 °C^-1 is heated from 20 °C to 100 °C in one minute. The mass of the solid is:

45.1 g

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48.1 g

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47.1 g

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52.1 g

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Solution

The correct option is D
52.1 g

Given:
The rate at which the burner is supplying heat, P = 50 Js^-1.
The time for which the burner has supplied heat, t = 1 min = 60 s.
The specific heat of the given solid, c = 0.72 Jg^-1 °C^-1
The change in temperature, θ_R = 100 - 20 = 80 °C
Required to find:
The mass of the solid. Let it be ‘m’.
Calculating the heat (H) supplied by the burner:
From the given, the heat supplied by the burner, $H = P \times t = 50 \times 60 = 3000 J$ .
Finding the mass (m) of the solid by using the formula (H = mcθ_R):
We know that Heat that is absorbed by a body, $H = m c θ_{R}$
by substituting the given values in the above expression, we get
$3000 = m x 0.72 x 80 = m x 57.6 \Rightarrow m = 52.1 g$
Therefore, the mass (m) of the given solid is 52.1 g.
Hence, option (D) is correct.

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A burner is supplying heat at a rate of 50 Js-1. A solid of specific heat capacity 0.72 Jg-1 °C-1 is heated from 20 °C to 100 °C in one minute. The mass of the solid is:

A burner is supplying heat at a rate of 50 Js^-1. A solid of specific heat capacity 0.72 Jg^-1 °C^-1 is heated from 20 °C to 100 °C in one minute. The mass of the solid is: