Question

a burner supplies heat energy at the rate of 20J/s, find the specific heat capacity of a solid of mass 25 g if its temp. rises by 80 °c in one minute?

Answer 1

Dear Student,

$$\begin{gathered} \mathrm{Heat}\mathrm{energy}\mathrm{supplied}\mathrm{by}\mathrm{burner}=20\mathrm{J}/\mathrm{s}\times 60\mathrm{s}=1200\mathrm{J} \\ \mathrm{Also},\mathrm{heat}\mathrm{energy}\mathrm{absorbed}\mathrm{by}\mathrm{solid}={\mathrm{mC\theta }}_{\mathrm{R}} \\ \mathrm{heat}\mathrm{energy}\mathrm{absorbed}\mathrm{by}\mathrm{solid}=25\times \mathrm{C}\times 80 \\ \mathrm{As},\mathrm{heat}\mathrm{supplied}=\mathrm{heat}\mathrm{absorbed} \\ 1200=25\times \mathrm{C}\times 80 \\ \mathrm{C}=\frac{1200}{25\times 80}=0.6\mathrm{J}/\mathrm{g}°\mathrm{C} \end{gathered}$$