A bus accelerates uniformly from rest and acquires a speed of $36$ $k m p h$ in $10 s$ . The acceleration is:

1 m / s^{2}

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2 m / s^{2}

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0.5 m / s^{2}

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3 m / s^{2}

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Solution

The correct option is A $1 m / s^{2}$
Given, the bus has started from rest.
Hence, initial velocity, $u = 0$ .
Given, final velocity, $v = 36 k m p h$ = $36 \times \frac{1000}{3600} m / s$
or, $v = 10$ m/s
Time, $t = 10 s$
$∴$ acceleration, $a = \frac{v - u}{t} = \frac{10 - 0}{10} = 1 m / s^{2}$

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