A bus can travel $10$ m in the first minute, $25$ m the next minute, $40$ m the third minute and so on in an arithmetic sequence. What is the total distance the bus travels in $10$ minutes?

2, 000

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775

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4, 000

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5, 000

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Solution

The correct option is C $775$
$a_{1} = 10 a_{2} = 25 a_{3} = 40 S_{n} = 10 + 25 + 40 + . . . + 10 t e r m s S_{n} = \frac{10}{2} (20 + 9 \times 15) S_{n} = 5 (20 + 135) S_{n} = 5 (155) S_{n} = 775$
Distance travelled $= 775 m e t r e s$

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