Question

A bus covers a distance of 250 km from Delhi to Jaipur towards west in 5 hours in the morning and returns to Delhi in the evening covering the same distance of 250 km in 5 hours. find :
a) Average speed
b) Average velocity of the bus for the whole journey

Answer 1

$$\begin{gathered} \left(\mathrm{a}\right)\mathrm{Average}\mathrm{speed}=\frac{\mathrm{Total}\mathrm{distance}\mathrm{travelled}}{\mathrm{time}\mathrm{taken}} \\ =\frac{250+250}{5+5}=\frac{500}{10}=50\mathrm{km}/\mathrm{h} \\ \left(\mathrm{b}\right)\mathrm{Average}\mathrm{velocity}=\frac{\mathrm{Total}\mathrm{displacement}}{\mathrm{time}\mathrm{taken}} \\ =\frac{\mathrm{Final}\mathrm{position}-\mathrm{Initial}\mathrm{position}}{\mathrm{Time}\mathrm{taken}}=\frac{0}{10}=0 \end{gathered}$$