A bus decreases its speed from $80 k m h^{- 1}$ to $60 k m h^{- 1}$ in 5 s. Find the acceleration of the bus.

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Solution

Initial speed $u = 80 k m / h = 80 \times \frac{5}{18} = 22.22 m / s$
Final speed $v = 60 k m / h = 60 \times \frac{5}{18} = 16.67 m / s$
Using $v = u + a t$
Or $16.67 = 22.22 + a \times 5$
$⟹ a = - 1.1 m / s^{2}$

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