A bus decreases its speed from $80 k m p h$ to $60 k m p h$ in 5 seconds. The retardation of the bus is:

$2.22 m s^{- 2}$

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$2.11 m s^{- 2}$

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$1.11 m s^{- 2}$

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$0 m s^{- 2}$

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Solution

The correct option is C
$1.11 m s^{- 2}$

Given, initial speed u = $80 k m p h$ = $80 \times \frac{5}{18}$ = $22.22 m s^{- 1}$
final speed v = $60 k m p h$ = $60 \times \frac{5}{18}$ = $16.66 m s^{- 1}$
and time taken t = 5 s
Let 'a' be the acceleration.
From the 1st equation of motion,
$a = \frac{v - u}{t}$ $= \frac{22.22 - 16.66}{5}$ = $- 1.11 m s^{- 2}$

Here sign of acceleration is negative and is termed as retardation which shows that the speed is decreasing.

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