A bus departs from the bus stand at $14 : 20$ hours. It takes $6$ hours and $23$ minutes to reach the destination bus stand. What will be the time of arrival shown on a $12 -$ hour clock?

$08 : 20$ PM

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$10 : 23$ AM

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$08 : 43$ PM

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$10 : 43$ PM

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Solution

The correct option is C
$08 : 43$ PM

The bus departs at $14 : 20$ hours.

After $6$ hours and $23$ minutes, the time will be $20 : 43$ hours.

We know that, $12 -$ hour time = ( $24 -$ hour time) - ( $12$ hours).

$\Rightarrow$ $20 : 43 h o u r s - 12 h o u r s$

$\Rightarrow$ $08 : 43 P M$

$∴$ The arrival time of the bus at the destination will be $08 : 43 P M$ .

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A bus departs from the bus stand at 14:20 hours. It takes 6 hours and 23 minutes to reach the destination bus stand. What will be the time of arrival shown on a 12−hour clock?

The correct option is C 08:43 PM The bus departs at 14:20 hours. After 6 hours and 23 minutes, the time will be 20:43 hours. We know that, 12−hour time = (24−hour time) - (12 hours). ⇒ 20:43 hours − 12 hours ⇒ 08:43 PM ∴ The arrival time of the bus at the destination will be 08:43 PM.

A bus departs from the bus stand at $14 : 20$ hours. It takes $6$ hours and $23$ minutes to reach the destination bus stand. What will be the time of arrival shown on a $12 -$ hour clock?