A bus driver completes a trip of $180$ km in $4$ hrs. If he averages $50$ km/hr during the first $3$ hrs of trip, then his speed in the final hour is

45

km/hr

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35

km/hr

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50

km/hr

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30

km/hr

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Solution

The correct option is D $30$ km/hr
Distance left = 180 - 50 $\times$ 3
= 180 - 150 = 30 km.
Time left = 4 - 3 = 1 hr
Speed $= \frac{D i s t a n c e}{T i m e} = \frac{30}{1}$
= 30 km/hr

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A bus driver completes a trip of 180 km in 4 hrs. If he averages 50 km/hr during the first 3 hrs of trip, then his speed in the final hour is

The correct option is D 30 km/hrDistance left = 180 - 50 × 3= 180 - 150 = 30 km.Time left = 4 - 3 = 1 hrSpeed =DistanceTime=301= 30 km/hr

A bus driver completes a trip of $180$ km in $4$ hrs. If he averages $50$ km/hr during the first $3$ hrs of trip, then his speed in the final hour is

The correct option is D $30$ km/hr
Distance left = 180 - 50 $\times$ 3
= 180 - 150 = 30 km.
Time left = 4 - 3 = 1 hr
Speed $= \frac{D i s t a n c e}{T i m e} = \frac{30}{1}$
= 30 km/hr