Question

A bus is moving with a speed of $65\frac{1}{2}km$ per hour.How much distance will it cover in $1\frac{1}{3}$ hours.

Answer 1

Convert the given mixed fraction into improper fraction

Given,
Speed of the bus per hour $=65\frac{1}{2}km$

$=\frac{2\times 65+1}{2}km$

$=\frac{131}{2}km$

Time taken $=1\frac{1}{3}$ hour

$=\frac{3\times 1+1}{3}hr$

$=\frac{4}{3}hr$

Finding the distance covered

we know,
Distance $=\text{speed}\times \text{time}$

$\therefore \text{Distace}=\frac{131}{2}\times \frac{4}{3}$

$=\frac{131\times 2\times 2}{2\times 3}$

$=\frac{262}{3}$

$=87\frac{1}{3}km$

Hence, the required distance is $87\frac{1}{3}km$