A bus is moving with a velocity of 5 m/s towards a huge wall. the driver sounds a horn of frequency 165 Hz. If the speed of sound in air is 355 m/s, the number of beats heard per second by a passenger on the bus will be approximately,

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Solution

The correct option is B
5

The apparent frequency heard by the passenger will be,

$n^{'}$ = $\frac{v + v_{B}}{v - v_{B}} \times n$ = $\frac{355 + 5}{355 - 5} \times 165$ = $170 H z$

Number of beats = $n^{'}$ - $n$ = 170 - 165 = 5 Hz

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A bus is moving with a velocity of 5 m/s towards a huge wall. the driver sounds a horn of frequency 165 Hz. If the speed of sound in air is 355 m/s, the number of beats heard per second by a passenger on the bus will be approximately,

The correct option is B 5 The apparent frequency heard by the passenger will be, n′ = v+vBv−vB × n = 355+5355−5 × 165 = 170 Hz Number of beats = n′ - n = 170 - 165 = 5 Hz

The correct option is B
5

The apparent frequency heard by the passenger will be,

$n^{'}$ = $\frac{v + v_{B}}{v - v_{B}} \times n$ = $\frac{355 + 5}{355 - 5} \times 165$ = $170 H z$

Number of beats = $n^{'}$ - $n$ = 170 - 165 = 5 Hz