A bus is moving with the initial velocity of u m/s .After applying brakes its retardation is 0.5 m/s^2 and it stopped after 12 secs.Find the initial velocity and distance travelled by the bus after applying brakes?

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Solution

$D e a r S t u d e n t, G i v e n t h e b u s i s m o v i n g w i t h i n i t i a l v e l o c i t y u . t = 12 s, a = - 0.5 m / s^{2} (R e t a r d a t i o n) v = 0 (A s t h e b u s s t o p s a f t e r a p p l y i n g b r a k e s .) W e h a v e, v = u + a t \Rightarrow 0 = u - 0.5 \times 12 \Rightarrow u = 6 m / s L e t t h e d i s \tan c e t r a v e l l e d a f t e r a p p l y i n g b r a k e s b e s, v^{2} = u^{2} + 2 a s \Rightarrow 0 = 36 - 2 \times 0.5 \times s \Rightarrow s = 36 m R e g a r d s$

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A bus is moving with the initial velocity of u m/s .After applying brakes its retardation is 0.5 m/s^2 and it stopped after 12 secs.Find the initial velocity and distance travelled by the bus after applying brakes?

Dear Student,Given the bus is moving with initial velocity u.t=12s,a=-0.5m/s2Retardationv=0(As the bus stops after applying brakes.)We have,v=u+at⇒0=u-0.5×12⇒u=6m/sLet the distance travelled after applying brakes be s,v2=u2+2as⇒0=36-2×0.5×s⇒s=36mRegards