A bus moving with 90 km/h speed, applies brake. It stops after 5 m. find the deceleration of the bus.

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Solution

Dear Student,

$initial velocity, u = 90 km / h u = 90 \times \frac{5}{18} m / s = 25 m / s final velocity, v = 0 distance, s = 5 m according to third equation of motion, v^{2} - u^{2} = 2 as {(0)}^{2} - {(25)}^{2} = 2 \times a \times 5 - 625 = 10 a a = - \frac{625}{10} = - 62.5 m / s^{2} here, negative sign indicates the retardation .$

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A bus moving with 90 km/h speed, applies brake. It stops after 5 m. find the deceleration of the bus.

Dear Student, initial velocity, u=90 km/hu=90×518 m/s=25 m/sfinal velocity, v=0distance, s=5 maccording to third equation of motion,v2-u2=2as02-252=2×a×5-625=10aa=-62510=-62.5 m/s2here, negative sign indicates the retardation.