A bus moving with uniform acceleration of $2 m / s^{2}$ passes with speed 5 m/s when a car acceleration at $4 m / s^{2}$ overtakes it. the velocity of the car is found to be 50 /m after 10s. the distance of separation between them after 10 s is

150 m

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75 m

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250 m

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300 m

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Solution

The correct option is A $150 m$
Initial Velocity of car $(u_{c}) = 50 - 4 (10) = 10 m / s$
Initial velocity of bus $(u_{b}) = 5 m / s$

Relative Initial velocity and acceleration of car with respect to bus is $5 m / s$ and $2 m / s^{2}$ .

Now, the separation after 10 seconds = $u t + \frac{1}{2} a t^{2}$

$= 5 (10) + \frac{1}{2} (2) (10)^{2} = 150 m$

Therefore, A is correct option.

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A bus moving with uniform acceleration of 2m/s2 passes with speed 5 m/s when a car acceleration at 4m/s2 overtakes it. the velocity of the car is found to be 50 /m after 10s. the distance of separation between them after 10 s is

The correct option is A 150mInitial Velocity of car (uc)=50−4(10)=10m/sInitial velocity of bus (ub)=5m/sRelative Initial velocity and acceleration of car with respect to bus is 5m/s and 2m/s2.Now, the separation after 10 seconds = ut+12at2=5(10)+12(2)(10)2=150mTherefore, A is correct option.

A bus moving with uniform acceleration of $2 m / s^{2}$ passes with speed 5 m/s when a car acceleration at $4 m / s^{2}$ overtakes it. the velocity of the car is found to be 50 /m after 10s. the distance of separation between them after 10 s is