You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Uniform and Non Uniform

A bus moving ...

Question

A bus moving with uniform acceleration of $2 m / s^{2}$ passes with speed 5 m/s when a car acceleration at $4 m / s^{2}$ overtakes it. the velocity of the car is found to be 50 /m after 10s. the distance of separation between them after 10 s is

150 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

75 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

250 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

300 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $150 m$
Initial Velocity of car $(u_{c}) = 50 - 4 (10) = 10 m / s$
Initial velocity of bus $(u_{b}) = 5 m / s$

Relative Initial velocity and acceleration of car with respect to bus is $5 m / s$ and $2 m / s^{2}$ .

Now, the separation after 10 seconds = $u t + \frac{1}{2} a t^{2}$

$= 5 (10) + \frac{1}{2} (2) (10)^{2} = 150 m$

Therefore, A is correct option.

Suggest Corrections

Similar questions

Q. A bus starts from rest and moves with constant acceleration

8 {m s}^{- 2}

. At. the same time, a car travelling with a constant velocity 16 m/s overtakes and passes the bus. After how much time and at what distance, the bus overtakes the car?

A car is moving with a uniform acceleration of $4 m / s^{2}$ . What distance will it cover in 10 seconds after the start?

Q. A motorbike is being chased by a car. The motorbike moves with the speed of

10 m / s

and has acceleration of

5 m / s^{2}

. Whereas, the car has speed of

20 m / s

and accelerates with

3 m / s^{2}

. If the initial separation between motorbike and car is

60 m

, find the distance by which car will miss the motorbike.

A car is moving with a uniform velocity of 10m/s .the driver of the car decides to overtake the bus moving ahead of the car.so the driver of the car accelerates at 1m/s²for 10 sec . Find the velocity of the car at the end of 10 sec.also find the distance travelled by the car while accelerating.

Q. A car is standing

200 m

behind a bus, which is also at rest. The two start moving at the same instant but with different forward accelerations. The bus has acceleration

2 m / s^{2}

and the car has acceleration

4 m / s^{2}

. The car will catch up with the bus after a time of:

Join BYJU'S Learning Program

A bus moving with uniform acceleration of 2m/s2 passes with speed 5 m/s when a car acceleration at 4m/s2 overtakes it. the velocity of the car is found to be 50 /m after 10s. the distance of separation between them after 10 s is

The correct option is A 150mInitial Velocity of car (uc)=50−4(10)=10m/sInitial velocity of bus (ub)=5m/sRelative Initial velocity and acceleration of car with respect to bus is 5m/s and 2m/s2.Now, the separation after 10 seconds = ut+12at2=5(10)+12(2)(10)2=150mTherefore, A is correct option.

A bus moving with uniform acceleration of $2 m / s^{2}$ passes with speed 5 m/s when a car acceleration at $4 m / s^{2}$ overtakes it. the velocity of the car is found to be 50 /m after 10s. the distance of separation between them after 10 s is