A bus power system network consists of 3 transmission line- The bus admittance matrix of the uncompensated system is-j6j3j4j3-j7j5j4j5-j8p-u- If the shunt capacitance of all the transmission lines is 50

nbsp; nbsp; nbsp; nbsp; y_31+y_32+y_30= j8 nbsp; nbsp; nbsp; nbsp; j_4 j_5+y_30= j8 nbsp; nbsp; nbsp; nbsp; nbsp; nb ...

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Power Systems

Y-Bus with Mutual Reactance

A bus power s...

Question

A bus power system network consists of 3 transmission line. The bus admittance matrix of the uncompensated system is
$⎛ ⎜ ⎝ \begin{matrix} - j 6 & j 3 & j 4 j 3 & - j 7 & j 5 j 4 & j 5 & - j 8 \end{matrix} ⎤ ⎥ ⎦ p . u .$
If the shunt capacitance of all the transmission lines is 50% compensated, the imaginary part of $3^{r d} r o w 3^{r d}$ column element in p.u. of the bus admittance matrix after compensation is

-j7

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-j8.5

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-j7.5

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-j9

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Solution

The correct option is B -j8.5
$y_{31} + y_{32} + y_{30} = - j 8$

$- j_{4} - j_{5} + y_{30} = - j 8$

$y_{30} = j 1$

After compensationn of 50%

${y_{30}}^{'} = j 1 \times 0.5$
New value = -j8 - j0.5
= -j 8.5

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Similar questions

Q. A 3-bus power system network consists of 3 transmission lines. The bus admittance matrix of the uncompensated system is

= ⎡ ⎢ ⎣ \begin{matrix} - j 6 & j 3 & j 4 j 3 & - j 7 & j 5 j 4 & j 5 & - j 8 \end{matrix} ⎤ ⎥ ⎦

pu
if the shunt capacitance of all transmission lines is 50% compensated, the imaginary part of the

3^{r d}

row

3^{r d}

column element (in pu) of the bus admittance matrix after compensation is

Q. The bus admittance matrix of a three-bus thee line system is

Y = j ⎡ ⎢ ⎣ \begin{matrix} - 13 & 10 & 5 10 & - 18 & 10 5 & 10 & - 13 \end{matrix} ⎤ ⎥ ⎦

If each transmission line between the two buses is represented by an equivalent

π

-network, the magnitude of the shunt susceptance of the line connecting bus 1 and 2 is

Q. For the 4-bus system, containing transmission lines and transformers. The admittance matrix is

Y_{b u s} = ⎡ ⎢ ⎢ ⎢ ⎢ ⎣ \begin{matrix} - j 20 & j 20 & 0 & 0 j 20 & - j 60 & j 40 & 0 0 & j 40 & - j 60 & j 20 0 & 0 & j 20 & - j 25 \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎥ ⎦

If a transmission line having

π

-equivalent circuit as shown below is connected between

2^{n d}

and

4^{t h}

buses. Then the modified

Y_{b u s}

matrix will be

Where,

Z_{s e}

= series impedance of transmission line.

Y_{s h} =

shunt admittance of transmission line.

Q. A three bus network is shown in the figure below indicating the p.u. impedances of each element.

The bus admittance matrix, Y-bus, of the network is

Q. Consider the three bus system shown below,

If the second row of the bus admittance matrix is

Y_{21} = 12.13 ∠ {104.04}^{\circ} p . u . Y_{22} = 24.23 ∠ - {75.95}^{\circ}

p.u and

Y_{23} = 12.13 ∠ {104.04}^{\circ}

p.u. , then the Jacobian matrix element

(\frac{\partial P_{2}}{\partial δ_{2}}) =

(Assume

V_{2}^{0}

=1+ j0 p.u. and

δ_{3}^{0}

=0)

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The correct option is B -j8.5 y31+y32+y30=−j8 −j4−j5+y30=−j8 y30=j1 After compensationn of 50% y30′=j1×0.5 New value = -j8 - j0.5 = -j 8.5

The correct option is B -j8.5
$y_{31} + y_{32} + y_{30} = - j 8$

$- j_{4} - j_{5} + y_{30} = - j 8$

$y_{30} = j 1$

After compensationn of 50%

${y_{30}}^{'} = j 1 \times 0.5$
New value = -j8 - j0.5
= -j 8.5