CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A bus starting from rest and moving with a uniform acceleration attains a speed 40 km/h in 10 minutes. Find its acceleration.


A

0.0185 m/s2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

0.185 m/s2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

0.09 m/s2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

0.0198 m/s2

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

0.0185 m/s2


Initial speed of bus, u = 0 m/s

Final speed of the bus, v = 40 km/h = 40×(518) m/s = 11.1 m/s

Time taken, t = 10 min = 600 s

Now, acceleration , a = vut = 11.10600 m/s2 = 0.0185 m/s2


flag
Suggest Corrections
thumbs-up
22
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Acceleration
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon