A bus starting from rest attain a velocity of $72 k m / h$ in $5$ sec. If the acceleration is uniform its acceleration in ( $m / s^{2}$ ) is

4

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $4$
Here,
Initial velocity is zero at $t = 0$ ,

final velocity $= 72 \times \frac{5}{18} = 20 m / s$

$t = 5 s$

$a = \frac{v}{t} = \frac{20}{5} = 4 m / s^{2}$

Suggest Corrections

Similar questions

A bus starting from rest and moving with a uniform acceleration attains a speed 40 km/h in 10 minutes. Find its acceleration.

Q. A train starting from rest attains a velocity of

72 k m / h

5

min. Assuming the acceleration is uniform; Find the acceleration and distance travelled by train for this velocity.

A car starts from rest . It moves with uniform acceleration. In 10sec it attains a speed of 72km/h on a straight road. Find its acceleration?

A train starting from rest attains a velocity of 72 km/h in 5 minutes. Assuming that the acceleration is uniform, find the acceleration and the distance travelled by train for attaining this velocity.

A bus accelerates uniformly 54 km/h to 72 km/h in 10 sec calculate acceleration in m/s²and distance covered by the bus in meters during this interval.

Join BYJU'S Learning Program

A bus starting from rest attain a velocity of 72km/h in 5 sec. If the acceleration is uniform its acceleration in (m/s2) is

The correct option is A 4Here,Initial velocity is zero at t=0,final velocity =72×518=20m/st=5sa=vt=205=4m/s2

A bus starting from rest attain a velocity of $72 k m / h$ in $5$ sec. If the acceleration is uniform its acceleration in ( $m / s^{2}$ ) is

The correct option is A $4$
Here,
Initial velocity is zero at $t = 0$ ,

final velocity $= 72 \times \frac{5}{18} = 20 m / s$

$t = 5 s$

$a = \frac{v}{t} = \frac{20}{5} = 4 m / s^{2}$