Question

A bus starting from rest moves with a uniform acceleration of $0.1m/s^2$ for $2mins$. Find

1. the speed acquired,
2. the distance traveled.

Answer 1

Step 1: Given

Initial velocity, $u=0$

Acceleration, $a=0.1m/s^2$

Time, $t=2mins=120s$

Step 2: Formula used

The first equation of motion, $v=u+at$

The third equation of motion,$v^2=u^2+2as$

Step 3: Determine the speed acquired

Let the final velocity be $v$

Using the first equation of motion,

$$\begin{gathered} v=u+at \\ =0+(0.1)\left(120\right) \\ =12m/s \end{gathered}$$

Step 4: Determine the distance travelled

Let the distance travelled be $s$

Using the third equation of motion,

$$\begin{gathered} v^2=u^2+2as \\ {12}^2=0^2+2(0.1)\left(s\right) \\ 144=0+0.2s \\ s=\frac{144}{0.2} \\ s=720m \end{gathered}$$

Therefore,

1. The speed acquired is $12m/s$
2. The distance travelled is $720m$