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# A bus starting from rest moves with a uniform acceleration of $0.1m/{s}^{2}$ for $2mins$. Find the speed acquired, the distance traveled.

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## Step 1: GivenInitial velocity, $u=0$Acceleration, $a=0.1m/{s}^{2}$Time, $t=2mins=120s$Step 2: Formula usedThe first equation of motion, $v=u+at$The third equation of motion,${v}^{2}={u}^{2}+2as$Step 3: Determine the speed acquiredLet the final velocity be $v$Using the first equation of motion,$v=u+at\phantom{\rule{0ex}{0ex}}=0+\left(0.1\right)\left(120\right)\phantom{\rule{0ex}{0ex}}=12m/s$Step 4: Determine the distance travelledLet the distance travelled be $s$Using the third equation of motion,${v}^{2}={u}^{2}+2as\phantom{\rule{0ex}{0ex}}{12}^{2}={0}^{2}+2\left(0.1\right)\left(s\right)\phantom{\rule{0ex}{0ex}}144=0+0.2s\phantom{\rule{0ex}{0ex}}s=\frac{144}{0.2}\phantom{\rule{0ex}{0ex}}s=720m$Therefore,The speed acquired is $12m/s$The distance travelled is $720m$  Suggest Corrections  68      Similar questions  Explore more