Question

A bus starts from city X. The number of women in the bus is half of the number of men. In city Y, $10$ men leave the bus and five women enter. Now, number of men and women is equal. How many passengers entered the bus in the beginning?

• A. $15$
• B. $30$
• C. $36$
• D. $45$

Answer 1

The correct option is D $45$

In city X, let the number of woman $=x$
Number of man$=2x$
In city Y $2x-10=x+5$
$x=15$
$\therefore$Total number of passengers in the beginning = $(x+2x)=3x=3\times 15=45.$