A bus starts from the stop and takes $50 s e c o n d s$ to attain the speed of $10 m s^{- 1}$ . If the mass of the bus along with the passengers is $10000 k g$ , calculate the net force acting on the bus to push it to the speed of $10 m s^{- 1}$ .

4000 N

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1000 N

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2000 N

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3000 N

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Solution

The correct option is C 2000 N
Given, initial velocity, $u = 0 m s^{- 1}$ , final velocity, $v = 10 m s^{- 1}$ and time taken, $t = 50 s$ .
Let the force be $F$ and acceleration be $a$ .
We know that, $F = m a$ and $a = \frac{v - u}{t}$
$∴$ $F = \frac{m (v - u)}{t} = \frac{10000 (10 - 0)}{50}$
$\Rightarrow F = 10000 \times \frac{1}{5}$
$\Rightarrow F = 2000 N$

Thus, the required force is 2000 N.

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A bus starts from the stop and takes 50 seconds to attain the speed of 10 $\frac{m}{s}$ . If the mass of the bus along with the passengers is 10000 kg, calculate the force applied (in N) by the engine of bus to push the bus to the speed of 10 $\frac{m}{s}$ .

___

A bus starts from the stop and takes $50 s e c o n d s$ to attain the speed of $10 m s^{- 1}$ . If the mass of the bus along with the passengers is $10000 k g$ , calculate the net force acting on the bus to push it to the speed of $10 m s^{- 1}$ .

Q. A bus starts from the stop and takes

50

second to get the speed of

10 m / s

. If the mass of the bus along with passengers is

10000 k g

, calculate the force applied by the engine of bus to push the bus at the speed of

10 m / s

A bus starts from the stop and takes $50$ seconds to attain the speed of $10 m / s$ . If the mass of the bus along with the passengers is $10000 k g$ , the force applied (in N) by the engine of the bus to attain the speed of $10 m / s$ is ___ N.

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A bus starts from the stop and takes 50 seconds to attain the speed of 10 ms−1. If the mass of the bus along with the passengers is 10000 kg, calculate the net force acting on the bus to push it to the speed of 10 ms−1.

The correct option is C 2000 NGiven, initial velocity, u=0 ms−1, final velocity, v=10 ms−1 and time taken, t=50 s. Let the force be F and acceleration be a. We know that, F=ma and a=v−ut ∴ F=m(v−u)t=10000(10−0)50 ⇒F=10000×15 ⇒F=2000 N Thus, the required force is 2000 N.

A bus starts from the stop and takes $50 s e c o n d s$ to attain the speed of $10 m s^{- 1}$ . If the mass of the bus along with the passengers is $10000 k g$ , calculate the net force acting on the bus to push it to the speed of $10 m s^{- 1}$ .