A bus starts from the stop and takes $50 s e c o n d s$ to attain the speed of $10 m s^{- 1}$ . If the mass of the bus along with the passengers is $10000 k g$ , calculate the net force acting on the bus to push it to the speed of $10 m s^{- 1}$ .

4000 N

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1000 N

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2000 N

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3000 N

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Solution

The correct option is C 2000 N
Given, initial velocity, $u = 0 m s^{- 1}$ , final velocity, $v = 10 m s^{- 1}$ and time taken, $t = 50 s$ .
Let the force be $F$ and acceleration be $a$ .
We know that, $F = m a$ and $a = \frac{v - u}{t}$
$∴$ $F = \frac{m (v - u)}{t} = \frac{10000 (10 - 0)}{50}$
$\Rightarrow F = 10000 \times \frac{1}{5}$
$\Rightarrow F = 2000 N$

Thus, the required force is 2000 N.

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50

second to get the speed of

10 m / s

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10000 k g

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A bus starts from the stop and takes 50 seconds to attain the speed of 10 ms−1. If the mass of the bus along with the passengers is 10000 kg, calculate the net force acting on the bus to push it to the speed of 10 ms−1.

The correct option is C 2000 NGiven, initial velocity, u=0 ms−1, final velocity, v=10 ms−1 and time taken, t=50 s. Let the force be F and acceleration be a. We know that, F=ma and a=v−ut ∴ F=m(v−u)t=10000(10−0)50 ⇒F=10000×15 ⇒F=2000 N Thus, the required force is 2000 N.

A bus starts from the stop and takes $50 s e c o n d s$ to attain the speed of $10 m s^{- 1}$ . If the mass of the bus along with the passengers is $10000 k g$ , calculate the net force acting on the bus to push it to the speed of $10 m s^{- 1}$ .