A bus starts its journey at $5 : 30$ a.m. and reaches its destination at $9 : 15$ p.m. with a stoppage time of $2$ hours. Find the ratio of the stoppage time to the total journey period.

12 : 95

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8 : 63

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4 : 73

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9 : 85

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Solution

The correct option is B $8 : 63$
Journey starts at $5 : 30 a m$ and
reaches destination at $9 : 15 p m$
$\to$ So Total journey period is $15 h r s 45 m i n$
Stoppage time is $2 h r s$ .
We have to find ratio of
$2 h r s : 15 : 45$
$1 h r - 60 m i n \to s o 2 h r s - 120 m i n$
$15 h r 45 m i n - 900 + 45 = 945 m i n$
$\frac{120}{945} = \frac{24}{189}$
i.e: $8 : 63$

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A bus starts its journey at 5:30 a.m. and reaches its destination at 9:15 p.m. with a stoppage time of 2 hours. Find the ratio of the stoppage time to the total journey period.

The correct option is B 8:63Journey starts at 5:30 am andreaches destination at 9:15 pm→ So Total journey period is 15 hrs 45 minStoppage time is 2 hrs.We have to find ratio of2 hrs:15:451 hr−60 min→ so 2 hrs−120 min15 hr 45 min−900+45=945 min120945=24189i.e: 8:63

A bus starts its journey at $5 : 30$ a.m. and reaches its destination at $9 : 15$ p.m. with a stoppage time of $2$ hours. Find the ratio of the stoppage time to the total journey period.