A bus traveling the first one third distance at a speed of 10km/hr, next one fourth at 20km/hr and the remaining at 40km/hr. The average speed of the bus is nearly

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Solution

let the total distance covered be x
thus
time takes to travel 1/3x = t1 = x/30

time taken to travel 1/4x = t2 = x/80

time taken to travel the rest = t3 = 5x/480 = x/96

thus average speed = total distnace/total time taken = 1/(1/30 + 1/80 + 1/96) kmph

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A bus traveling the first one third distance at a speed of 10km/hr, next one fourth at 20km/hr and the remaining at 40km/hr. The average speed of the bus is nearly

let the total distance covered be x thus time takes to travel 1/3x = t1 = x/30 time taken to travel 1/4x = t2 = x/80 time taken to travel the rest = t3 = 5x/480 = x/96 thus average speed = total distnace/total time taken = 1/(1/30 + 1/80 + 1/96) kmph

let the total distance covered be x
thus
time takes to travel 1/3x = t1 = x/30

time taken to travel 1/4x = t2 = x/80

time taken to travel the rest = t3 = 5x/480 = x/96

thus average speed = total distnace/total time taken = 1/(1/30 + 1/80 + 1/96) kmph