A bus travels a distance of 120km with a speed of 40km/h and returns with a speed of30km/h. Calculat the average speed for the entire journey.

34.2 km / hr

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

32.4 km / hr

No worries! We‘ve got your back. Try BYJU‘S free classes today!

30 km / hr

No worries! We‘ve got your back. Try BYJU‘S free classes today!

40 km / hr

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is
A

34.2 km / hr

Distance = 120 km
speed= 40 km / hr
speed = distance / time
time = distance/ speed= 3 hour

for return of bus
distance = 120 km
speed = 30 km/ hr
time = 4 hr

average speed $= \frac{t o t a l d i s t a n c e}{t o t a l t i m e t a k e n}$

$= \frac{(120 + 120)}{(3 + 4)}$
$= 34.2 k m / h r$

Suggest Corrections

417

Similar questions

If a car travels a distance of 120 km with a speed of 80 km/h and returns with a speed of 60 km/h. Calculate the average velocity for the entire journey.

A train travels 40 km at a uniform speed of $30 k m / h r$ . Its average speed after travelling another 40 km is $45 k m / h r$ for the whole journey. Find its speed in the second half of the journey.

a) A train travels a distance with a speed of 40 km/h and returns with a speed of 60 km/h. Calculate the average speed of the train.

b) On a 60 km track, a train travels the first 30 km at a uniform speed of 30 km/h. How fast must a train travel the next 30 km so that the average speed is 40 km/hr for the entire trip?

What is the relative speed when a train with a speed of 40 km/hr crosses a car traveling at the speed of 70 km/hr moving in the same direction.

A boat leaves it's dock and travels upstream at a speed of 40 km/hr and then returns to the dock. What is the speed of the stream if they average speed of the entire trip is 60 km/hr?

Join BYJU'S Learning Program

A bus travels a distance of 120km with a speed of 40km/h and returns with a speed of30km/h. Calculat the average speed for the entire journey.

The correct option is A 34.2 km / hrDistance = 120 km speed= 40 km / hr speed = distance / time time = distance/ speed= 3 hour for return of bus distance = 120 km speed = 30 km/ hr time = 4 hr average speed =total distancetotal time taken =(120+120)(3+4)=34.2 km/hr