A businessman, by means of a false balance defrauds to an extent of 10% in buying goods and 10% in selling goods. Then, by how much percent does he gain?

21%

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20%

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19%

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18%

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Solution

The correct option is A 21%
Let us assume that if the dealer buys 100 units of a article he defrauds to an extent of 10%
he buys 10% more
fraud in buying= $100 + \frac{10}{100} \times 100 = 110 u n i t s$
In selling he sells 110 units at 10% profit
$110 + \frac{10}{100} \times 110 = 121 u n i t s$
gain made will be121-100=21 units
gain percantage= $\frac{21}{100} \times 100 = 21$ %

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