A businessman sold a cycle at $8 %$ profit. If the cost had been $10 %$ less and selling price Rs. 36 less, he would have made a profit of $12 %$ . The cost price of the cycle is Rs.___.

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Solution

Let the cost price of the cycle be Rs. 100x
So, its sale price $= R s . 108 \times [P r o f i t i s 8 %]$
Secondly, when the cost price is $10 %$ less
i.e., when the cost price = Rs. (100x -10x) = Rs. 90x
The profit $= 12 %$ of Rs. 90x $= R s . (\frac{12}{100}) \times 90 x = R s . \frac{108 x}{10}$
Its sale price $= R s . 90 + R s . (\frac{108}{10}) = R s . \frac{1008}{10}$
First sale price - Second sale price = Rs. 36
$R s . 108 x - R s . \frac{1008 x}{10} = R s . 36$
Or, $\frac{(1080 x - 1008 x)}{10} = R s . 36$
Or, $\frac{72 x}{10} = R s . 36$
Or, $x = 5$
Cost price of the cycle = Rs. 100x = Rs. 500

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A businessman sold a cycle at 8% profit. If the cost had been 10% less and selling price Rs. 36 less, he would have made a profit of 12%. The cost price of the cycle is Rs.___.

A businessman sold a cycle at $8 %$ profit. If the cost had been $10 %$ less and selling price Rs. 36 less, he would have made a profit of $12 %$ . The cost price of the cycle is Rs.___.