Question

A buzzing bumblebee flaps its wings 4000 times in 8 seconds. What is the time period of its wings?

• A. $6ms$
• B. $10ms$
• C. $5ms$
• D. $2ms$

Answer 1

The correct option is D $2ms$

Given:
A bumblebee's wings vibrate 4000 times in a span of 8 seconds.
$⟹$ In one second, they vibrate $\frac{4000}{8}=500$ times.
Frequency of an object is defined as the number of times the object vibrates in one second.
So, the frequency ($f$) of the bumblebee's wings is $500\text{Hz}$.
Time period ($T$) is the inverse of frequency.
$⟹T=\frac{1}{f}=\frac{1}{500}=0.002s$
$T=2\times {10}^{-3}s=2ms$