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Question

a+bx, x<14,b-ax, x>128. Suppose f(x)=x=1and if limf (x)-f (1) what are possible values of a and b?

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Solution

Let the given function defined over their range as

f( x )={ a+bx,x<1 4,x=1 bax,x>1

We need to find the possible values of a and b from the given function.

From the definition of limits, we know that:

lim xa f( x )=f( a )

On substituting the values into the expressions, we get

lim x 1 f( x )= lim x 1 ( a+bx ) = lim x1 ( a+bx ) =( a+b1 ) =( a+b ) (1)

lim x 1 + f( x )= lim x 1 + ( bax ) = lim x1 ( bax ) =( ba1 ) =( ba ) (2)

Also it is given that,

lim x1 f( x )=f( 1 )

The value of f( 1 )=4 (3)

We know that the limit of a function at a particular point only exists if its left hand limit is equal to the right hand limit. That is:

lim x 1 f( x )= lim x 1 + f( x )= lim x1 f( x )

From equations (1), (2) and (3), we get

a+b=4 (4)

And

ba=4 (5)

On solving equations (4) and (5), we get

2b=8 b=4

Putting the value of b in equation (3), we get

a=0

Thus, the possible value of a and b is 0 and 4 respectively.


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