a _ c _ abb _ a _ bc _ bc _ ab

c b c a a a

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b c c c a b

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b c c a a c

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a c b a b c

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Solution

The correct option is C b c c a a c
The series is a b c c a b | b c a a b c | a b c c a b
Here, the pattern a b c c a b | b c a a b c is repeated alternatively.

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Similar questions

$a^{2} + b c + a b + a c = ? (a) (a + b) (a + c) (b) (a + b) (b + c) (c) (b + c) (c + a) (d) a (a + b + c)$

Q. Tick (✓) the correct answer:
a² + bc + ab + ac = ?
(a) (a + b)(a + c)
(b) (a + b)(b + c)
(c) (b + c)(c + a)
(d) a(a + b + c)

$Express the det A = ∣ ∣ ∣ ∣ \begin{matrix} a & b c & a b c b & c a & a b c c & a b & a b c \end{matrix} ∣ ∣ ∣ ∣ as product of factors$

The determinant
$∣ ∣ ∣ ∣ ∣ \begin{matrix} b^{2} - a b & b - c & b c - a c a b - a^{2} & a - b & b^{2} - a b b c - a c & c - a & a b - a^{2} \end{matrix} ∣ ∣ ∣ ∣ ∣$ equals to:

(a) abc(b-c)(c-a)(a-b)
(b) (b-c)(c-a)(a-b)
(c) (a+b+c)(b-c)(c-a)(a-b)
(d) None of these

Q. Evaluate

\frac{(a - b)^{2}}{(b - c) (c - a)} + \frac{(b - c)^{2}}{(a - b) (c - a)} + \frac{(c - a)^{2}}{(a - b) (b - c)}

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a _ c _ abb _ a _ bc _ bc _ ab

The correct option is C b c c a a cThe series is a b c c a b | b c a a b c | a b c c a bHere, the pattern a b c c a b | b c a a b c is repeated alternatively.

The correct option is C b c c a a c
The series is a b c c a b | b c a a b c | a b c c a b
Here, the pattern a b c c a b | b c a a b c is repeated alternatively.