Question

$A+C\left(carbon\right)\underset{Hightemp}{\overset{\Delta }{\to }}B+G\left(gas\right)G\left(gas\right)+O_2\underset{Burnwithblueflame}{\overset{}{\to }}D\left(gas\right)B+H_{2}O⟶F+H\left(gas\right)$
$A+H_{2}O⟶F$
$F+D\left(gas\right)\to$ milky solution, Milky solution disappears if more gas D is passed
$B+N_2\stackrel{\Delta }{\to }J+Carbon$

List-I contains questions related to information given above and List-II contains their answer(s) as compounds from above information.
$\begin{array}{cc}\text{List - I}& \text{List - II}\\ \text{(I)Which oxygen containing compound(s) is/are}& \text{(P) J}\\ \text{basic in nature?}& \\ \text{(II) Which compound(s) on hydrolysis can give urea?}& \text{(Q) B}\\ \text{(III) Which compound(s) has/have triple bond or}& \text{(R) F}\\ \text{bond order equal to 3 but not contain(s) nitrogen?}& \\ \text{(IV) Which gas(es) on combustion give(s) D}& \text{(S) A}\\ & \text{(T) G}\\ & \text{(U) H}\end{array}$

Which of the following options has the correct combination considering Lists-I, II?

• A. (I), (S) and (II), (U)
• B. (I), (R) (S) (T) and (II), (P)
• C. (I), (Q) (R) (S) (U) and (II), (U)
• D. (I), (R) (S) and (II), (P)

Answer 1

The correct option is D (I), (R) (S) and (II), (P)

Since $F+D\to milkysolution$, So $D\left(gas\right)=C{O}_2$
and $F=Ca(OH{)}_2$.
Given, $A+H_{2}O\to Ca(OH{)}_2$
Thus, $A=CaO$
Again, $CaO+carbon\stackrel{\Delta }{\to }B+G\left(gas\right)$
$\therefore B=Ca{C}_2$
Also, G (gas) burns with blue flame. So, it is $CO$
Given, $Ca{C}_2+N_2\stackrel{\Delta }{\to }J+Carbon$
$\therefore J=CaC{N}_2$
$Ca{C}_2+H_{2}O⟶Ca(OH{)}_2+H(gas)$
$H\left(gas\right)=C_2{H}_2$
So, we have,
$CaOandCa(OH{)}_2$ as oxygen containing compounds which are basic in nature
$Ca(CN{)}_2$ on reaction with water gives urea.