A cabin is moving vertically upwards with an acceleration a. A massless string is attached to the ceiling of the cabin on which a bead of mass m is sliding downwards with respect to string with an acceleration a. The tension in the string is
A
m(g−a)
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B
m(g=a)
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C
m(g+2a)
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D
mg
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Solution
The correct option is Dmg Let's say we observe the bead with respect to string. Now, the string itself is accelerated up with ′a′
Hence, on the bead pseudo force ma will act downward and it's acceleration is a downward (with respect to string)
Let T be the tension in the string
From FBD we have, ma+mg−T=ma ⇒T=mg
Hence, option (C) is correct.