Question

A cable of insignificant weight, 18 m long, is supported at its two ends, 16 m apart, at the same level. The cable supports at its mid-reach a load of 120N. The tension in the cable is nearly

• A. 131 N
• B. 126 N
• C. 121 N
• D. 136 N

Answer 1

The correct option is A 131 N

FBD of joint C,
$2T\sin \theta =120$

$\Rightarrow T=\frac{120}{2\times \frac{OC}{CA}}=\frac{120}{2\times \left(\frac{\sqrt{9^2-8^2}}{9}\right)}$
$\Rightarrow T=130.96N$