Question

A cable PQ of length 25 m is supported at two ends at same level as shown in the figure. The horizontal distance between the supports is 20 m. A point load of 150 kN is applied at point R, which divides it into two equal parts.





Neglecting the self-weight of the cable, the tension (in kN, in integer value) in the cable due to applied load will be____

• A. 125

Answer 1

The correct option is A 125

$OR=\sqrt{(12.5{)}^2-(10{)}^2}=7.5m$

$V_1=V_2=75kN$

$\sum M_R=0\text{(of left hand side)}$

$H_1\times OR=V_1\times 10$

$H_1=\frac{75\times 10}{7.5}=100kN$

$\therefore \text{Tension in the cable}$

$T=\sqrt{H_1^2+V_1^2}$

$=\sqrt{{100}^2+{75}^2}$

$=125kN$