A cable that can support a load of 1000 N is cut into equal parts. the maximum load that can be supported by the either part is:-

1000 N

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2000 N

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500 N

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250 N

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Solution

The correct option is A 1000 N
Maximum load supported by the cable is directly proportional to the breaking stress.

Since,

Breaking stress = F / A

where F is the force and A is the cross-sectional area.

As we see that the breaking stress is independent of the length of the cable. So, if the cable is cut in two equal parts, the maximum load that can be supported by either parts of the cable remain the same as before.

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