A caesium photocell, with a steady potential difference of 60V across, is illuminated by a bright point source of light 50 cm away. When the same light is placed 1m away the photoelectrons emitted from the cell
Are one quarter as numerous
Number of photo electrons
(N)∝Intensity∝1d2⇒N1N2=(d2d1)2
⇒N1N2=(10050)2=41⇒N2=N14