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Question
(a) Calculate the heat capacity of a copper vessel of mass 150 g if the specific heat capacity of copper is 410 J kg−1 K−1.
(b) How much heat energy will be required to increase the temperature of the vessel in part(a) from 25∘C to 35∘C?
(a) Calculate the heat capacity of a copper vessel of mass 150 g if the specific heat capacity of copper is 410 J kg−1 K−1.
(b) How much heat energy will be required to increase the temperature of the vessel in part(a) from 25∘C to 35∘C?
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Solution
(i) Heat capacity = Mass × Specifc heat capacity
= 150×10−3kg×410J/(kgK)
= 61.5 J / K
The heat capacity of copper is 61.5 J/K
(ii) Q=m⋅c⋅ΔT ,
where; Q - heat absorbed
m - the mass of the sample
c - the specific heat of the substance
ΔT - the change in temperature, defined as final temperature minus initial temperature
ΔT = 35o−25o = 10o
Q = 150× 10−3× 410× 10
Q = 615 J
(i) Heat capacity = Mass × Specifc heat capacity
= 150×10−3kg×410J/(kgK)
= 61.5 J / K
The heat capacity of copper is 61.5 J/K
(ii) Q=m⋅c⋅ΔT ,
where; Q - heat absorbed
m - the mass of the sample
c - the specific heat of the substance
ΔT - the change in temperature, defined as final temperature minus initial temperature
ΔT = 35o−25o = 10o
Q = 150× 10−3× 410× 10
Q = 615 J
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